What is the answer to (6-l)+(3m)i=-12+27i ?

The answer to (6-l)+(3m)i=-12+27i is l=18,m=9

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(6-l)+(3m)i=-12+27i

(6 - l) + (3 m) i = - 12 + 27 i

l = 18, m = 9

Solution steps

(6 - l) + (3 m) i = - 12 + 27 i

Rewrite

(6 - l) + (3 m) i

in standard complex form:

(6 - l) + 3 mi

(6 - l) + 3 mi = - 12 + 27 i

Complex numbers can be equal only if their real and imaginary parts are equalRewrite as system of equations:

[6 - l = - 12 3 m = 27]

[6 - l = - 12 3 m = 27] : l = 18, m = 9

l = 18, m = 9

a^{2} + b^{2} + 2 a + 2 bi = 12 + 6 i

z^{2} + (1 - 2 i) z - 3 - i = 0

x, f s i f (x) = x^{2}

(a + bi)^{2} = 13 - 12 i

z^{2} + 5 z + 15 + 3 i = 0

What is the answer to (6-l)+(3m)i=-12+27i ?
The answer to (6-l)+(3m)i=-12+27i is l=18,m=9