What is the answer to a^2+b^2+2a+2bi=12+6i ?

The answer to a^2+b^2+2a+2bi=12+6i is

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a^2+b^2+2a+2bi=12+6i

a^{2} + b^{2} + 2 a + 2 bi = 12 + 6 i

(a = 1, a = - 3, b = 3 b = 3)

Solution steps

a^{2} + b^{2} + 2 a + 2 bi = 12 + 6 i

Complex numbers can be equal only if their real and imaginary parts are equalRewrite as system of equations:

[a^{2} + b^{2} + 2 a = 12 2 b = 6]

[a^{2} + b^{2} + 2 a = 12 2 b = 6] : (a = 1, a = - 3, b = 3 b = 3)

(a = 1, a = - 3, b = 3 b = 3)

z^{2} + (1 - 2 i) z - 3 - i = 0

x, f s i f (x) = x^{2}

(a + bi)^{2} = 13 - 12 i

z^{2} + 5 z + 15 + 3 i = 0

(3 k + 2) + (4 m) i = - 4 + 20 i

What is the answer to a^2+b^2+2a+2bi=12+6i ?
The answer to a^2+b^2+2a+2bi=12+6i is