What is the answer to (8+9i)y-(3+6i)x=16-3i ?

The answer to (8+9i)y-(3+6i)x=16-3i is x=8,y=5

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(8+9i)y-(3+6i)x=16-3i

(8 + 9 i) y - (3 + 6 i) x = 16 - 3 i

x = 8, y = 5

Solution steps

(8 + 9 i) y - (3 + 6 i) x = 16 - 3 i

Rewrite

(8 + 9 i) y - (3 + 6 i) x

in standard complex form:

(8 y - 3 x) + (9 y - 6 x) i

(8 y - 3 x) + (9 y - 6 x) i = 16 - 3 i

Complex numbers can be equal only if their real and imaginary parts are equalRewrite as system of equations:

[8 y - 3 x = 16 9 y - 6 x = - 3]

[8 y - 3 x = 16 9 y - 6 x = - 3] : x = 8, y = 5

x = 8, y = 5

(5 - 3 i) y - (6 + 2 i) x = 3 - 41 i

x^{2} + y^{2} - (x + i y) = 1 + 0 i

a = [aij]

∣ z + 1 - i ∣ = 1

\frac{2 - 2 i}{4} = \frac{1 - 2 i}{z}

What is the answer to (8+9i)y-(3+6i)x=16-3i ?
The answer to (8+9i)y-(3+6i)x=16-3i is x=8,y=5