What are the solutions to the equation 2x^2+13x+6=0 ?

The solutions to the equation 2x^2+13x+6=0 are x=-1/2 ,x=-6

Find the zeros of 2x^2+13x+6=0

The zeros of 2x^2+13x+6=0 are x=-1/2 ,x=-6

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2 x^{2} + 13 x + 6 = 0

x = - \frac{1}{2}, x = - 6

Solution steps

2 x^{2} + 13 x + 6 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 13 \pm 1 3 ^{2} - 4 \cdot 2 \cdot 6}{2 \cdot 2}

1 3^{2} - 4 \cdot 2 \cdot 6 = 11

x_{1, 2} = \frac{- 13 \pm 11}{2 \cdot 2}

Separate the solutions

x_{1} = \frac{- 13 + 11}{2 \cdot 2}, x_{2} = \frac{- 13 - 11}{2 \cdot 2}

x = \frac{- 13 + 11}{2 \cdot 2} : - \frac{1}{2}

x = \frac{- 13 - 11}{2 \cdot 2} : - 6

The solutions to the quadratic equation are:

x = - \frac{1}{2}, x = - 6

- \frac{3}{4} x + 3 > 11

x^{2} + 4 x + 3 x + 12

\frac{1}{2} y - \frac{1}{3} y - \frac{3}{11} y = \frac{1}{2}

∣ 6 - x ∣ = 10

\frac{6 + 7 i}{6 - 7 i}

What are the solutions to the equation 2x^2+13x+6=0 ?
The solutions to the equation 2x^2+13x+6=0 are x=-1/2 ,x=-6
Find the zeros of 2x^2+13x+6=0
The zeros of 2x^2+13x+6=0 are x=-1/2 ,x=-6