What is the answer to (1+i)(x+yi)=1+3i ?

The answer to (1+i)(x+yi)=1+3i is x=2,y=1

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(1+i)(x+yi)=1+3i

(1 + i) (x + y i) = 1 + 3 i

x = 2, y = 1

Solution steps

(1 + i) (x + y i) = 1 + 3 i

Expand

(1 + i) (x + y i) : (x - y) + i (x + y)

(x - y) + i (x + y) = 1 + 3 i

Complex numbers can be equal only if their real and imaginary parts are equalRewrite as system of equations:

[x - y = 1 x + y = 3]

[x - y = 1 x + y = 3] : x = 2, y = 1

x = 2, y = 1

4 z^{2} - 4 z + 3 - 23 i = 0

(x + y i) (2 + 3 i) = 1 - 5 i

4 a - 3 i = 6 + bi

∣ a - i ∣ = 37

x^{2} - 2 i x - 2 = 0

What is the answer to (1+i)(x+yi)=1+3i ?
The answer to (1+i)(x+yi)=1+3i is x=2,y=1