What is the answer to siP(x)=2x-1,Q(x)=x+3 ?

The answer to siP(x)=2x-1,Q(x)=x+3 is

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siP(x)=2x-1,Q(x)=x+3

s i P (x) = 2 x - 1, Q (x) = x + 3

(s = 0, s \in R, x = \frac{1}{2}, x = \frac{1}{2}, P \in R P = 0)

Solution steps

s i P (x) = 2 x - 1

Rewrite

s i P (x)

in standard complex form:

0 + s P (x) i

0 + s P (x) i = 2 x - 1

Rewrite

2 x - 1

in standard complex form:

(2 x - 1) + 0 i

0 + s P (x) i = (2 x - 1) + 0 i

Complex numbers can be equal only if their real and imaginary parts are equalRewrite as system of equations:

[0 = 2 x - 1 s P (x) = 0]

[0 = 2 x - 1 s P (x) = 0] : (s = 0, s \in R, x = \frac{1}{2}, x = \frac{1}{2}, P \in R P = 0)

(s = 0, s \in R, x = \frac{1}{2}, x = \frac{1}{2}, P \in R P = 0)

2 x - y + (2 x - 3 y - i) i = 0

(a + bi)^{2} + 4 (a + bi) = - 4 - 2 i

z^{2} - (2 + 3 i) z - 5 + i = 0

\frac{( 41 + 3 i )}{65} = \frac{1}{x}

i x^{2} - 2 (i + 1) x + 10 = 0

What is the answer to siP(x)=2x-1,Q(x)=x+3 ?
The answer to siP(x)=2x-1,Q(x)=x+3 is