What is the answer to x+iy-4i=3y-2ix+9 ?

The answer to x+iy-4i=3y-2ix+9 is x=3,y=-2

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x+iy-4i=3y-2ix+9

x + i y - 4 i = 3 y - 2 i x + 9

x = 3, y = - 2

Solution steps

x + i y - 4 i = 3 y - 2 i x + 9

Rewrite

x + i y - 4 i

in standard complex form:

x + (y - 4) i

x + (y - 4) i = 3 y - 2 i x + 9

Rewrite

3 y - 2 i x + 9

in standard complex form:

(3 y + 9) - 2 x i

x + (y - 4) i = (3 y + 9) - 2 x i

Complex numbers can be equal only if their real and imaginary parts are equalRewrite as system of equations:

[x = 3 y + 9 y - 4 = - 2 x]

[x = 3 y + 9 y - 4 = - 2 x] : x = 3, y = - 2

x = 3, y = - 2

(x + y) - 16 i = 12 + (x - y) i

z = \frac{2 + ai}{1 - i}

x + y i = 3 i - 4 + 2 - 6 i + \frac{1}{2} i

x (2 - 4 i) - 5 = x - (7 + y i)

l, y = \frac{x}{l in x}

What is the answer to x+iy-4i=3y-2ix+9 ?
The answer to x+iy-4i=3y-2ix+9 is x=3,y=-2