What is the answer to (2x+y)+(3i-5xi)=1-7i ?

The answer to (2x+y)+(3i-5xi)=1-7i is x=2,y=-3

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(2x+y)+(3i-5xi)=1-7i

(2 x + y) + (3 i - 5 x i) = 1 - 7 i

x = 2, y = - 3

Solution steps

(2 x + y) + (3 i - 5 x i) = 1 - 7 i

Rewrite

(2 x + y) + (3 i - 5 x i)

in standard complex form:

(2 x + y) + (3 - 5 x) i

(2 x + y) + (3 - 5 x) i = 1 - 7 i

Complex numbers can be equal only if their real and imaginary parts are equalRewrite as system of equations:

[2 x + y = 1 3 - 5 x = - 7]

[2 x + y = 1 3 - 5 x = - 7] : x = 2, y = - 3

x = 2, y = - 3

0.005 x i = \frac{1}{0.000018 x i}

z^{2} - (3 + 6 i) z - 4 - 6 i = 0

i (x + i y) = x + i + i 2 y

4 - i x = y - 3 i

a^{2} i - b^{2} i = - a^{2} + b^{2} i l

What is the answer to (2x+y)+(3i-5xi)=1-7i ?
The answer to (2x+y)+(3i-5xi)=1-7i is x=2,y=-3