What is the answer to (x^2-2x-15)+(3y-9)i=3i ?

The answer to (x^2-2x-15)+(3y-9)i=3i is

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(x^2-2x-15)+(3y-9)i=3i

(x^{2} - 2 x - 15) + (3 y - 9) i = 3 i

(x = - 3, x = 5, y = 4 y = 4)

Solution steps

(x^{2} - 2 x - 15) + (3 y - 9) i = 3 i

Rewrite

3 i

in standard complex form:

0 + 3 i

(x^{2} - 2 x - 15) + (3 y - 9) i = 0 + 3 i

Complex numbers can be equal only if their real and imaginary parts are equalRewrite as system of equations:

[x^{2} - 2 x - 15 = 0 3 y - 9 = 3]

[x^{2} - 2 x - 15 = 0 3 y - 9 = 3] : (x = - 3, x = 5, y = 4 y = 4)

(x = - 3, x = 5, y = 4 y = 4)

3 ai - b - 3 i = a - 5 + bi

∣ z - 1 + 3 i ∣ = 2

∣ x + bi + 1 + i ∣ = 1

(z^{2} + i) = 0

4 - x i = y - 3 i

What is the answer to (x^2-2x-15)+(3y-9)i=3i ?
The answer to (x^2-2x-15)+(3y-9)i=3i is