What is the answer to (x+yi)=(1-ai)/(1+ai) ?

The answer to (x+yi)=(1-ai)/(1+ai) is x=(1-a^2)/(1+a^2),y=-(2a)/(1+a^2)

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(x+yi)=(1-ai)/(1+ai)

(x + y i) = \frac{1 - ai}{1 + ai}

x = \frac{1 - a ^{2}}{1 + a ^{2}}, y = - \frac{2 a}{1 + a ^{2}}

Solution steps

(x + y i) = \frac{1 - ai}{1 + ai}

Simplify

x + i y = \frac{1 - a ^{2}}{1 + a ^{2}} - i \frac{2 a}{1 + a ^{2}}

Complex numbers can be equal only if their real and imaginary parts are equalRewrite as system of equations:

[x = \frac{1 - a ^{2}}{1 + a ^{2}} y = - \frac{2 a}{1 + a ^{2}}]

[x = \frac{1 - a ^{2}}{1 + a ^{2}} y = - \frac{2 a}{1 + a ^{2}}] : x = \frac{1 - a ^{2}}{1 + a ^{2}}, y = - \frac{2 a}{1 + a ^{2}}

x = \frac{1 - a ^{2}}{1 + a ^{2}}, y = - \frac{2 a}{1 + a ^{2}}

m, r = \frac{i - m}{1 + m}

- 9 x + 8 i = - 54 + (16 y) i

x^{2} - (2 - 4 i) x - (3 + 6 i) = 0

y - 8 = 3 (x + 1) in

x, R s i R (x) = 8 - 2 x + x^{2}

What is the answer to (x+yi)=(1-ai)/(1+ai) ?
The answer to (x+yi)=(1-ai)/(1+ai) is x=(1-a^2)/(1+a^2),y=-(2a)/(1+a^2)