What are the solutions to the equation 6x^2-4x-3=0 ?

The solutions to the equation 6x^2-4x-3=0 are x=(2+sqrt(22))/6 ,x=(2-sqrt(22))/6

Find the zeros of 6x^2-4x-3=0

The zeros of 6x^2-4x-3=0 are x=(2+sqrt(22))/6 ,x=(2-sqrt(22))/6

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6 x^{2} - 4 x - 3 = 0

x = \frac{2 + 22}{6}, x = \frac{2 - 22}{6}

Decimal Notation

x = 1.11506 \dots, x = - 0.44840 \dots

Solution steps

6 x^{2} - 4 x - 3 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 4 ) \pm ( - 4 ) ^{2} - 4 \cdot 6 ( - 3 )}{2 \cdot 6}

(- 4)^{2} - 4 \cdot 6 (- 3) = 222

x_{1, 2} = \frac{- ( - 4 ) \pm 2 22}{2 \cdot 6}

Separate the solutions

x_{1} = \frac{- ( - 4 ) + 2 22}{2 \cdot 6}, x_{2} = \frac{- ( - 4 ) - 2 22}{2 \cdot 6}

x = \frac{- ( - 4 ) + 2 22}{2 \cdot 6} : \frac{2 + 22}{6}

x = \frac{- ( - 4 ) - 2 22}{2 \cdot 6} : \frac{2 - 22}{6}

The solutions to the quadratic equation are:

x = \frac{2 + 22}{6}, x = \frac{2 - 22}{6}

3 x^{2} + 2 < 4 x^{2}

3 (\frac{3}{4})

- \frac{1}{2} x^{- 2} y^{- 4}

2 x^{2} + 19 x + 24

\frac{1. 9 ^{2} - 4}{1.9 - 2}

What are the solutions to the equation 6x^2-4x-3=0 ?
The solutions to the equation 6x^2-4x-3=0 are x=(2+sqrt(22))/6 ,x=(2-sqrt(22))/6
Find the zeros of 6x^2-4x-3=0
The zeros of 6x^2-4x-3=0 are x=(2+sqrt(22))/6 ,x=(2-sqrt(22))/6