What are the solutions to the equation x^2+14x+47=7 ?

The solutions to the equation x^2+14x+47=7 are x=-4,x=-10

Find the zeros of x^2+14x+47=7

The zeros of x^2+14x+47=7 are x=-4,x=-10

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

x^{2} + 14 x + 47 = 7

x = - 4, x = - 10

Solution steps

x^{2} + 14 x + 47 = 7

Move

7

to the left side

x^{2} + 14 x + 40 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 14 \pm 1 4 ^{2} - 4 \cdot 1 \cdot 40}{2 \cdot 1}

1 4^{2} - 4 \cdot 1 \cdot 40 = 6

x_{1, 2} = \frac{- 14 \pm 6}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 14 + 6}{2 \cdot 1}, x_{2} = \frac{- 14 - 6}{2 \cdot 1}

x = \frac{- 14 + 6}{2 \cdot 1} : - 4

x = \frac{- 14 - 6}{2 \cdot 1} : - 10

The solutions to the quadratic equation are:

x = - 4, x = - 10

- \frac{3}{2} x - (- x - 1) = - 6 x + 2 (4 x - \frac{1}{4})

2 x + 1 \geq 7

x \cdot y

5 y - 3 (y - 4) + 2 = 7

\frac{1}{2 - 5 i}

What are the solutions to the equation x^2+14x+47=7 ?
The solutions to the equation x^2+14x+47=7 are x=-4,x=-10
Find the zeros of x^2+14x+47=7
The zeros of x^2+14x+47=7 are x=-4,x=-10