What is the answer to 5y-3(y-4)+2=7 ?

The answer to 5y-3(y-4)+2=7 is y=-7/2

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5y-3(y-4)+2=7

5 y - 3 (y - 4) + 2 = 7

y = - \frac{7}{2}

Solution steps

5 y - 3 (y - 4) + 2 = 7

Move

2

to the right side

5 y - 3 (y - 4) = 5

Expand

- 3 (y - 4) : - 3 y + 12

5 y - 3 y + 12 = 5

Add similar elements:

5 y - 3 y = 2 y

2 y + 12 = 5

Move

12

to the right side

2 y = - 7

Divide both sides by

2

y = - \frac{7}{2}

\frac{1}{2 - 5 i}

49 x^{4} - 121 y^{6}

12 r^{2} - 64 r + 80

10.36 - 0.094 \cdot 0 + 0.131 \cdot 16 + 0.21 \cdot 16

- 4 \leq t \leq 5