What are the solutions to the equation -5x^2-14x+3=0 ?

The solutions to the equation -5x^2-14x+3=0 are x=-3,x= 1/5

Find the zeros of -5x^2-14x+3=0

The zeros of -5x^2-14x+3=0 are x=-3,x= 1/5

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- 5 x^{2} - 14 x + 3 = 0

x = - 3, x = \frac{1}{5}

Solution steps

- 5 x^{2} - 14 x + 3 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 14 ) \pm ( - 14 ) ^{2} - 4 ( - 5 ) \cdot 3}{2 ( - 5 )}

(- 14)^{2} - 4 (- 5) \cdot 3 = 16

x_{1, 2} = \frac{- ( - 14 ) \pm 16}{2 ( - 5 )}

Separate the solutions

x_{1} = \frac{- ( - 14 ) + 16}{2 ( - 5 )}, x_{2} = \frac{- ( - 14 ) - 16}{2 ( - 5 )}

x = \frac{- ( - 14 ) + 16}{2 ( - 5 )} : - 3

x = \frac{- ( - 14 ) - 16}{2 ( - 5 )} : \frac{1}{5}

The solutions to the quadratic equation are:

x = - 3, x = \frac{1}{5}

2 (x - 1)^{2} = 6

- 5 x^{2} + 4 x + 1 = 0

(- \frac{i}{2})^{2}

49 k^{4} - 9

(15 x y^{2}) (\frac{1}{3} x^{2} z^{3}) (y^{3} z^{4})

What are the solutions to the equation -5x^2-14x+3=0 ?
The solutions to the equation -5x^2-14x+3=0 are x=-3,x= 1/5
Find the zeros of -5x^2-14x+3=0
The zeros of -5x^2-14x+3=0 are x=-3,x= 1/5