What are the solutions to the equation -5x^2+4x+1=0 ?

The solutions to the equation -5x^2+4x+1=0 are x=-1/5 ,x=1

Find the zeros of -5x^2+4x+1=0

The zeros of -5x^2+4x+1=0 are x=-1/5 ,x=1

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- 5 x^{2} + 4 x + 1 = 0

x = - \frac{1}{5}, x = 1

Decimal Notation

x = - 0.2, x = 1

Solution steps

- 5 x^{2} + 4 x + 1 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 4 \pm 4 ^{2} - 4 ( - 5 ) \cdot 1}{2 ( - 5 )}

4^{2} - 4 (- 5) \cdot 1 = 6

x_{1, 2} = \frac{- 4 \pm 6}{2 ( - 5 )}

Separate the solutions

x_{1} = \frac{- 4 + 6}{2 ( - 5 )}, x_{2} = \frac{- 4 - 6}{2 ( - 5 )}

x = \frac{- 4 + 6}{2 ( - 5 )} : - \frac{1}{5}

x = \frac{- 4 - 6}{2 ( - 5 )} : 1

The solutions to the quadratic equation are:

x = - \frac{1}{5}, x = 1

(- \frac{i}{2})^{2}

49 k^{4} - 9

(15 x y^{2}) (\frac{1}{3} x^{2} z^{3}) (y^{3} z^{4})

(x - 4)^{2} - 31 = 30

3 (2 v + 8) = 60

What are the solutions to the equation -5x^2+4x+1=0 ?
The solutions to the equation -5x^2+4x+1=0 are x=-1/5 ,x=1
Find the zeros of -5x^2+4x+1=0
The zeros of -5x^2+4x+1=0 are x=-1/5 ,x=1