What is the answer to ((D+3I)^2+4I)^2y=0 ?

The answer to ((D+3I)^2+4I)^2y=0 is I=(-3D-2+2sqrt(3D+1))/9 ,I=-(3D+2sqrt(3D+1)+2)/9 ,y=0

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((D+3I)^2+4I)^2y=0

((D + 3 I)^{2} + 4 I)^{2} y = 0

I = \frac{- 3 D - 2 + 2 3 D + 1}{9}, I = - \frac{3 D + 2 3 D + 1 + 2}{9}, y = 0

Solution steps

((D + 3 I)^{2} + 4 I)^{2} y = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

(D + 3 I)^{2} + 4 I = 0 or y = 0

Solve

(D + 3 I)^{2} + 4 I = 0 : I = \frac{- 3 D - 2 + 2 3 D + 1}{9}, I = - \frac{3 D + 2 3 D + 1 + 2}{9}

y = 0

The solutions are

I = \frac{- 3 D - 2 + 2 3 D + 1}{9}, I = - \frac{3 D + 2 3 D + 1 + 2}{9}, y = 0

2 x y^{2} = 0, 2 x^{2} y = 0

2 r (s + 1)^{2} = 0

(x t^{1}) = 0

2 r (s + 1)^{2} = 0, 2 r^{2} (s + 1) = 0

(x + 2) (y - 1)^{3} (2 x - 1) = 0

What is the answer to ((D+3I)^2+4I)^2y=0 ?
The answer to ((D+3I)^2+4I)^2y=0 is I=(-3D-2+2sqrt(3D+1))/9 ,I=-(3D+2sqrt(3D+1)+2)/9 ,y=0