What is the answer to 10^x-8(5^x)-2^x+8=0 ?

The answer to 10^x-8(5^x)-2^x+8=0 is x=0,x=3

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10^x-8(5^x)-2^x+8=0

1 0^{x} - 8 (5^{x}) - 2^{x} + 8 = 0

x = 0, x = 3

Solution steps

1 0^{x} - 8 (5^{x}) - 2^{x} + 8 = 0

Factor

1 0^{x} - 8 (5^{x}) - 2^{x} + 8 : (5^{x} - 1) (2^{x} - 8)

(5^{x} - 1) (2^{x} - 8) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

5^{x} - 1 = 0 or 2^{x} - 8 = 0

Solve

5^{x} - 1 = 0 : x = 0

Solve

2^{x} - 8 = 0 : x = 3

The solutions are

x = 0, x = 3

(x - 2) (y - 3) = 0

y \cdot e^{x} = 0

(x - 1) y - y = 0

M (2 x^{2} + 128 x - 4096) = 0

I n (x) = 0

What is the answer to 10^x-8(5^x)-2^x+8=0 ?
The answer to 10^x-8(5^x)-2^x+8=0 is x=0,x=3
Solve for x: 10^x-8(5^x)-2^x+8=0
The solution is x=0,x=3