What are the solutions to the equation 7x^2+6x-1=0 ?

The solutions to the equation 7x^2+6x-1=0 are x= 1/7 ,x=-1

Find the zeros of 7x^2+6x-1=0

The zeros of 7x^2+6x-1=0 are x= 1/7 ,x=-1

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7 x^{2} + 6 x - 1 = 0

x = \frac{1}{7}, x = - 1

Solution steps

7 x^{2} + 6 x - 1 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 6 \pm 6 ^{2} - 4 \cdot 7 ( - 1 )}{2 \cdot 7}

6^{2} - 4 \cdot 7 (- 1) = 8

x_{1, 2} = \frac{- 6 \pm 8}{2 \cdot 7}

Separate the solutions

x_{1} = \frac{- 6 + 8}{2 \cdot 7}, x_{2} = \frac{- 6 - 8}{2 \cdot 7}

x = \frac{- 6 + 8}{2 \cdot 7} : \frac{1}{7}

x = \frac{- 6 - 8}{2 \cdot 7} : - 1

The solutions to the quadratic equation are:

x = \frac{1}{7}, x = - 1

- 9 (x - 5) + 9 < 3 x + 42

8 x + 9 < 16 x - 8

\frac{1}{- \frac{15}{17}}

(\frac{5}{9})^{3}

3 n^{3} - 4 n^{2} + 9 n - 12

What are the solutions to the equation 7x^2+6x-1=0 ?
The solutions to the equation 7x^2+6x-1=0 are x= 1/7 ,x=-1
Find the zeros of 7x^2+6x-1=0
The zeros of 7x^2+6x-1=0 are x= 1/7 ,x=-1