What are the solutions to the equation 7x^2=3x^2+25 ?

The solutions to the equation 7x^2=3x^2+25 are x= 5/2 ,x=-5/2

Find the zeros of 7x^2=3x^2+25

The zeros of 7x^2=3x^2+25 are x= 5/2 ,x=-5/2

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7 x^{2} = 3 x^{2} + 25

x = \frac{5}{2}, x = - \frac{5}{2}

Solution steps

7 x^{2} = 3 x^{2} + 25

Move

3 x^{2}

to the left side

4 x^{2} = 25

Divide both sides by

4

x^{2} = \frac{25}{4}

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

x = \frac{25}{4}, x = - \frac{25}{4}

\frac{25}{4} = \frac{5}{2}

- \frac{25}{4} = - \frac{5}{2}

x = \frac{5}{2}, x = - \frac{5}{2}

0 = 2 x^{2} + 3 x

- 4 (3 x + 2) = - 3 (4 x + 5)

x + 9 \geq 9 and x + 6 \leq 5

\frac{2}{3} x < 14

What are the solutions to the equation 7x^2=3x^2+25 ?
The solutions to the equation 7x^2=3x^2+25 are x= 5/2 ,x=-5/2
Find the zeros of 7x^2=3x^2+25
The zeros of 7x^2=3x^2+25 are x= 5/2 ,x=-5/2