What is the answer to (9x)^2+yx(9x)+81x^2=0 ?

The answer to (9x)^2+yx(9x)+81x^2=0 is x=0,y=-18

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(9x)^2+yx(9x)+81x^2=0

(9 x)^{2} + y x (9 x) + 81 x^{2} = 0

x = 0, y = - 18

Solution steps

(9 x)^{2} + y x (9 x) + 81 x^{2} = 0

Factor

(9 x)^{2} + y x (9 x) + 81 x^{2} : 9 x^{2} (y + 18)

9 x^{2} (y + 18) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

x = 0 or y + 18 = 0

x = 0

Solve

y + 18 = 0 : y = - 18

The solutions are

x = 0, y = - 18

(x^{2} - 4) (y^{2} - 9) = 0

(D - 2 I)^{3} y = 0

2 t (u - 1)^{4} = 0

- 4 y - (x^{4} + 7 x^{2} + 10) y = 0

(x^{2} + 9) y^{1} + x y = 0

What is the answer to (9x)^2+yx(9x)+81x^2=0 ?
The answer to (9x)^2+yx(9x)+81x^2=0 is x=0,y=-18