What is the answer to 0=-X+3X(1+r)^{-2} ?

The answer to 0=-X+3X(1+r)^{-2} is X=0,r=sqrt(3)-1,r=-sqrt(3)-1

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

0=-X+3X(1+r)^{-2}

0 = - X + 3 X (1 + r)^{- 2}

X = 0, r = 3 - 1, r = - 3 - 1

Decimal Notation

X = 0, r = 0.73205 \dots, r = - 2.73205 \dots

Solution steps

0 = - X + 3 X (1 + r)^{- 2}

Switch sides

- X + 3 X (1 + r)^{- 2} = 0

Factor

- X + 3 X (1 + r)^{- 2} : X (- 1 + \frac{3}{( 1 + r ) ^{2}})

X (- 1 + \frac{3}{( 1 + r ) ^{2}}) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

X = 0 or - 1 + \frac{3}{( 1 + r ) ^{2}} = 0

X = 0

Solve

- 1 + \frac{3}{( 1 + r ) ^{2}} = 0 : r = 3 - 1, r = - 3 - 1

The solutions are

X = 0, r = 3 - 1, r = - 3 - 1

m y + k y = 0

4500 (\frac{1 + r}{12})^{156} = 0

y, x y + 4 x = 0

2 x y - 4 x = 0, y^{2} + x^{2} - 4 y = 0, 2 x

4 x y + (2 + x) y = 0

What is the answer to 0=-X+3X(1+r)^{-2} ?
The answer to 0=-X+3X(1+r)^{-2} is X=0,r=sqrt(3)-1,r=-sqrt(3)-1