What is the answer to 2xy-4x=0,y^2+x^2-4y=0,2x ?

The answer to 2xy-4x=0,y^2+x^2-4y=0,2x is x=0,y=2

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2xy-4x=0,y^2+x^2-4y=0,2x

2 x y - 4 x = 0, y^{2} + x^{2} - 4 y = 0, 2 x

x = 0, y = 2

Solution steps

2 x y - 4 x = 0

Factor

2 x y - 4 x : 2 x (y - 2)

2 x (y - 2) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

x = 0 or y - 2 = 0

x = 0

Solve

y - 2 = 0 : y = 2

The solutions are

x = 0, y = 2

4 x y + (2 + x) y = 0

2 (y + 4)^{2} (x - 1) = 0

(x^{2} + 1) (y^{2} + 1) = 0

s v (s) + 2 v (s) = 0

e^{2 x} 2 y = 0

What is the answer to 2xy-4x=0,y^2+x^2-4y=0,2x ?
The answer to 2xy-4x=0,y^2+x^2-4y=0,2x is x=0,y=2