What is the answer to In(4-x)+In(4x)=0 ?

The answer to In(4-x)+In(4x)=0 is I=0,x=-4/3 ;\quad n\ne 0

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In(4-x)+In(4x)=0

I n (4 - x) + I n (4 x) = 0

I = 0, x = - \frac{4}{3}; n \neq = 0

Decimal Notation

I = 0, x = - 1.33333 \dots

Solution steps

I n (4 - x) + I n (4 x) = 0

Factor

I n (4 - x) + I n (4 x) : n I (4 + 3 x)

n I (4 + 3 x) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

I = 0 or 4 + 3 x = 0

I = 0

Solve

4 + 3 x = 0 : x = - \frac{4}{3}

The solutions are

I = 0, x = - \frac{4}{3}; n \neq = 0

2 y m + y = 0

(1 + x) y = 0

x ∣ x ∣ = 0

x^{2} y + x y - y k^{2} = 0

n y ((2 - x)^{3} - (2 - x)) = 0

What is the answer to In(4-x)+In(4x)=0 ?
The answer to In(4-x)+In(4x)=0 is I=0,x=-4/3 ;\quad n\ne 0