What is the answer to (x^2+1)(y-y^2)=0 ?

The answer to (x^2+1)(y-y^2)=0 is y=0,y=1

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(x^2+1)(y-y^2)=0

(x^{2} + 1) (y - y^{2}) = 0

y = 0, y = 1

Solution steps

(x^{2} + 1) (y - y^{2}) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

x^{2} + 1 = 0 or y - y^{2} = 0

Solve

x^{2} + 1 = 0 : x = i, x = - i

Solve

y - y^{2} = 0 : y = 0, y = 1

The solutions are

Remove complex solutions:

x = i, x = - i

y = 0, y = 1

2 x^{7} - 256 x^{4.6} = 0

- 400 (4 x + 1)^{99} = 0

- (1 + x) y = 0

d^{2} y d x^{2} - 2 (d y d x) + 4 y = 0

x, e^{2 x - y} + e^{y - 2 x} = 0

What is the answer to (x^2+1)(y-y^2)=0 ?
The answer to (x^2+1)(y-y^2)=0 is y=0,y=1