What are the solutions to the equation (x-8)^2-13(x-8)+30=0 ?

The solutions to the equation (x-8)^2-13(x-8)+30=0 are x=18,x=11

Find the zeros of (x-8)^2-13(x-8)+30=0

The zeros of (x-8)^2-13(x-8)+30=0 are x=18,x=11

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(x - 8)^{2} - 13 (x - 8) + 30 = 0

x = 18, x = 11

Solution steps

(x - 8)^{2} - 13 (x - 8) + 30 = 0

Expand

(x - 8)^{2} - 13 (x - 8) + 30 : x^{2} - 29 x + 198

x^{2} - 29 x + 198 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 29 ) \pm ( - 29 ) ^{2} - 4 \cdot 1 \cdot 198}{2 \cdot 1}

(- 29)^{2} - 4 \cdot 1 \cdot 198 = 7

x_{1, 2} = \frac{- ( - 29 ) \pm 7}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 29 ) + 7}{2 \cdot 1}, x_{2} = \frac{- ( - 29 ) - 7}{2 \cdot 1}

x = \frac{- ( - 29 ) + 7}{2 \cdot 1} : 18

x = \frac{- ( - 29 ) - 7}{2 \cdot 1} : 11

The solutions to the quadratic equation are:

x = 18, x = 11

9 x^{4} - 6 x^{3} + 4 x^{2}

lo g_{10} (100) = x

\frac{5}{2 c - 7} > 1

\frac{10 2}{2}

\frac{7 - 19}{- 3 - 1}

What are the solutions to the equation (x-8)^2-13(x-8)+30=0 ?
The solutions to the equation (x-8)^2-13(x-8)+30=0 are x=18,x=11
Find the zeros of (x-8)^2-13(x-8)+30=0
The zeros of (x-8)^2-13(x-8)+30=0 are x=18,x=11