The solution to 5/(2c-7)>1 is 7/2 <c<6

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5/(2c-7)>1

Solution

\frac{5}{2 c - 7} > 1

\frac{7}{2} < c < 6

Solution steps

\frac{5}{2 c - 7} > 1

Rewrite in standard form

\frac{- 2 c + 12}{2 c - 7} > 0

Factor

\frac{- 2 c + 12}{2 c - 7} : \frac{- 2 ( c - 6 )}{2 c - 7}

\frac{- 2 ( c - 6 )}{2 c - 7} > 0

Multiply both sides by

- 1

(reverse the inequality)

\frac{( - 2 ( c - 6 ) ) ( - 1 )}{2 c - 7} < 0 \cdot (- 1)

Simplify

\frac{2 ( c - 6 )}{2 c - 7} < 0

Divide both sides by

2

\frac{\frac{2 ( c - 6 )}{2 c - 7}}{2} < \frac{0}{2}

Simplify

\frac{c - 6}{2 c - 7} < 0

Identify the intervals

\frac{7}{2} < c < 6

\frac{10 2}{2}

\frac{7 - 19}{- 3 - 1}

- 7 x - 2 = - 2

1.05 x^{2} - 3.1 x - 6.2 = 0

2124 x^{2} + 5609 x + 5662 = 124000