What are the solutions to the equation a^2-9a+20=0 ?

The solutions to the equation a^2-9a+20=0 are a=5,a=4

Find the zeros of a^2-9a+20=0

The zeros of a^2-9a+20=0 are a=5,a=4

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

a^{2} - 9 a + 20 = 0

a = 5, a = 4

Solution steps

a^{2} - 9 a + 20 = 0

Solve with the quadratic formula

a_{1, 2} = \frac{- ( - 9 ) \pm ( - 9 ) ^{2} - 4 \cdot 1 \cdot 20}{2 \cdot 1}

(- 9)^{2} - 4 \cdot 1 \cdot 20 = 1

a_{1, 2} = \frac{- ( - 9 ) \pm 1}{2 \cdot 1}

Separate the solutions

a_{1} = \frac{- ( - 9 ) + 1}{2 \cdot 1}, a_{2} = \frac{- ( - 9 ) - 1}{2 \cdot 1}

a = \frac{- ( - 9 ) + 1}{2 \cdot 1} : 5

a = \frac{- ( - 9 ) - 1}{2 \cdot 1} : 4

The solutions to the quadratic equation are:

a = 5, a = 4

3 r^{2} + 16 r + 5

- 3 y^{2} + 5 y - 6 = 0

4 x - 3 = 2 x + 7

\frac{1}{2} \cdot 2^{1}

2 x^{2} + 5 x - 4 = - 1

What are the solutions to the equation a^2-9a+20=0 ?
The solutions to the equation a^2-9a+20=0 are a=5,a=4
Find the zeros of a^2-9a+20=0
The zeros of a^2-9a+20=0 are a=5,a=4