What are the solutions to the equation -3y^2+5y-6=0 ?

The solutions to the equation -3y^2+5y-6=0 are y= 5/6-i(sqrt(47))/6 ,y= 5/6+i(sqrt(47))/6

Find the zeros of -3y^2+5y-6=0

The zeros of -3y^2+5y-6=0 are y= 5/6-i(sqrt(47))/6 ,y= 5/6+i(sqrt(47))/6

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- 3 y^{2} + 5 y - 6 = 0

y = \frac{5}{6} - i \frac{47}{6}, y = \frac{5}{6} + i \frac{47}{6}

Solution steps

- 3 y^{2} + 5 y - 6 = 0

Solve with the quadratic formula

y_{1, 2} = \frac{- 5 \pm 5 ^{2} - 4 ( - 3 ) ( - 6 )}{2 ( - 3 )}

Simplify

5^{2} - 4 (- 3) (- 6) : 47 i

y_{1, 2} = \frac{- 5 \pm 47 i}{2 ( - 3 )}

Separate the solutions

y_{1} = \frac{- 5 + 47 i}{2 ( - 3 )}, y_{2} = \frac{- 5 - 47 i}{2 ( - 3 )}

y = \frac{- 5 + 47 i}{2 ( - 3 )} : \frac{5}{6} - i \frac{47}{6}

y = \frac{- 5 - 47 i}{2 ( - 3 )} : \frac{5}{6} + i \frac{47}{6}

The solutions to the quadratic equation are:

y = \frac{5}{6} - i \frac{47}{6}, y = \frac{5}{6} + i \frac{47}{6}

4 x - 3 = 2 x + 7

\frac{1}{2} \cdot 2^{1}

2 x^{2} + 5 x - 4 = - 1

- 7 w^{2} + 30 w - 8

What are the solutions to the equation -3y^2+5y-6=0 ?
The solutions to the equation -3y^2+5y-6=0 are y= 5/6-i(sqrt(47))/6 ,y= 5/6+i(sqrt(47))/6
Find the zeros of -3y^2+5y-6=0
The zeros of -3y^2+5y-6=0 are y= 5/6-i(sqrt(47))/6 ,y= 5/6+i(sqrt(47))/6