What is expand (2x+1)(x^2+4x-5) ?

The solution to expand (2x+1)(x^2+4x-5) is 2x^3+9x^2-6x-5

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

expand (2x+1)(x^2+4x-5)

expand

(2 x + 1) (x^{2} + 4 x - 5)

2 x^{3} + 9 x^{2} - 6 x - 5

Solution steps

(2 x + 1) (x^{2} + 4 x - 5)

Distribute parentheses

= 2 x x^{2} + 2 x \cdot 4 x + 2 x (- 5) + 1 \cdot x^{2} + 1 \cdot 4 x + 1 \cdot (- 5)

Simplify

2 x x^{2} + 2 x \cdot 4 x + 2 x (- 5) + 1 \cdot x^{2} + 1 \cdot 4 x + 1 \cdot (- 5) : 2 x^{3} + 9 x^{2} - 6 x - 5

= 2 x^{3} + 9 x^{2} - 6 x - 5

6 \times 25

- - 93

+ 2 n^{2} - 3 n - 9

\frac{30}{15}

\frac{2}{x} + \frac{1}{x + 1} - 3

What is expand (2x+1)(x^2+4x-5) ?
The solution to expand (2x+1)(x^2+4x-5) is 2x^3+9x^2-6x-5