What are the solutions to the equation x^2+4x-73=x-3 ?

The solutions to the equation x^2+4x-73=x-3 are x=7,x=-10

Find the zeros of x^2+4x-73=x-3

The zeros of x^2+4x-73=x-3 are x=7,x=-10

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x^{2} + 4 x - 73 = x - 3

x = 7, x = - 10

Solution steps

x^{2} + 4 x - 73 = x - 3

Move

3

to the left side

x^{2} + 4 x - 70 = x

Move

x

to the left side

x^{2} + 3 x - 70 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 3 \pm 3 ^{2} - 4 \cdot 1 \cdot ( - 70 )}{2 \cdot 1}

3^{2} - 4 \cdot 1 \cdot (- 70) = 17

x_{1, 2} = \frac{- 3 \pm 17}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 3 + 17}{2 \cdot 1}, x_{2} = \frac{- 3 - 17}{2 \cdot 1}

x = \frac{- 3 + 17}{2 \cdot 1} : 7

x = \frac{- 3 - 17}{2 \cdot 1} : - 10

The solutions to the quadratic equation are:

x = 7, x = - 10

- 19 x - 19 = - 19 x - 19

(- 2 ab)^{3} (a c^{3}) (ll b c^{2})

x^{2} + 12 x + 43 = 0

- 9 x + 8 > 5 (8 - x)

f (k) = \frac{5 k ^{2} - 26 k + 5}{25 k ^{3} - k}

What are the solutions to the equation x^2+4x-73=x-3 ?
The solutions to the equation x^2+4x-73=x-3 are x=7,x=-10
Find the zeros of x^2+4x-73=x-3
The zeros of x^2+4x-73=x-3 are x=7,x=-10