What are the solutions to the equation x^2+12x+43=0 ?

The solutions to the equation x^2+12x+43=0 are x=-6+sqrt(7)i,x=-6-sqrt(7)i

Find the zeros of x^2+12x+43=0

The zeros of x^2+12x+43=0 are x=-6+sqrt(7)i,x=-6-sqrt(7)i

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x^{2} + 12 x + 43 = 0

x = - 6 + 7 i, x = - 6 - 7 i

Solution steps

x^{2} + 12 x + 43 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 12 \pm 1 2 ^{2} - 4 \cdot 1 \cdot 43}{2 \cdot 1}

Simplify

1 2^{2} - 4 \cdot 1 \cdot 43 : 27 i

x_{1, 2} = \frac{- 12 \pm 2 7 i}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 12 + 2 7 i}{2 \cdot 1}, x_{2} = \frac{- 12 - 2 7 i}{2 \cdot 1}

x = \frac{- 12 + 2 7 i}{2 \cdot 1} : - 6 + 7 i

x = \frac{- 12 - 2 7 i}{2 \cdot 1} : - 6 - 7 i

The solutions to the quadratic equation are:

x = - 6 + 7 i, x = - 6 - 7 i

- 9 x + 8 > 5 (8 - x)

8 (t + 2) - 3 (t - 4) = 6 (t - 7) + 8

g - 6 \geq 2

\frac{7 r ^{4} s ^{6} t ^{7}}{9 r ^{1} s ^{2} t ^{8}}

18 x^{2} - 50

What are the solutions to the equation x^2+12x+43=0 ?
The solutions to the equation x^2+12x+43=0 are x=-6+sqrt(7)i,x=-6-sqrt(7)i
Find the zeros of x^2+12x+43=0
The zeros of x^2+12x+43=0 are x=-6+sqrt(7)i,x=-6-sqrt(7)i