What are the solutions to the equation -3x^2-18x-35=0 ?

The solutions to the equation -3x^2-18x-35=0 are x=-3-i(2sqrt(6))/3 ,x=-3+i(2sqrt(6))/3

Find the zeros of -3x^2-18x-35=0

The zeros of -3x^2-18x-35=0 are x=-3-i(2sqrt(6))/3 ,x=-3+i(2sqrt(6))/3

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- 3 x^{2} - 18 x - 35 = 0

x = - 3 - i \frac{2 6}{3}, x = - 3 + i \frac{2 6}{3}

Solution steps

- 3 x^{2} - 18 x - 35 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 18 ) \pm ( - 18 ) ^{2} - 4 ( - 3 ) ( - 35 )}{2 ( - 3 )}

Simplify

(- 18)^{2} - 4 (- 3) (- 35) : 46 i

x_{1, 2} = \frac{- ( - 18 ) \pm 4 6 i}{2 ( - 3 )}

Separate the solutions

x_{1} = \frac{- ( - 18 ) + 4 6 i}{2 ( - 3 )}, x_{2} = \frac{- ( - 18 ) - 4 6 i}{2 ( - 3 )}

x = \frac{- ( - 18 ) + 4 6 i}{2 ( - 3 )} : - 3 - i \frac{2 6}{3}

x = \frac{- ( - 18 ) - 4 6 i}{2 ( - 3 )} : - 3 + i \frac{2 6}{3}

The solutions to the quadratic equation are:

x = - 3 - i \frac{2 6}{3}, x = - 3 + i \frac{2 6}{3}

19 x + 18 = - 19 x + 18

(x - 1) (x + 5) = 0

∣ 4 x + 3 ∣ = 3 - x

5 (6 x + 1) - 18 x = 3 (4 x - 2)

What are the solutions to the equation -3x^2-18x-35=0 ?
The solutions to the equation -3x^2-18x-35=0 are x=-3-i(2sqrt(6))/3 ,x=-3+i(2sqrt(6))/3
Find the zeros of -3x^2-18x-35=0
The zeros of -3x^2-18x-35=0 are x=-3-i(2sqrt(6))/3 ,x=-3+i(2sqrt(6))/3