What are the solutions to the equation (x-1)(x+5)=0 ?

The solutions to the equation (x-1)(x+5)=0 are x=1,x=-5

Find the zeros of (x-1)(x+5)=0

The zeros of (x-1)(x+5)=0 are x=1,x=-5

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(x - 1) (x + 5) = 0

x = 1, x = - 5

Solution steps

(x - 1) (x + 5) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

x - 1 = 0 or x + 5 = 0

Solve

x - 1 = 0 : x = 1

Solve

x + 5 = 0 : x = - 5

The solutions to the quadratic equation are:

x = 1, x = - 5

∣ 4 x + 3 ∣ = 3 - x

5 (6 x + 1) - 18 x = 3 (4 x - 2)

(4 j - 2)^{2} - (2 + 4 j)^{2}

60 a + 64 \geq 80 a - 9260 a + 64 \geq 80 a - 92

k^{2} + k - 2

What are the solutions to the equation (x-1)(x+5)=0 ?
The solutions to the equation (x-1)(x+5)=0 are x=1,x=-5
Find the zeros of (x-1)(x+5)=0
The zeros of (x-1)(x+5)=0 are x=1,x=-5