What is factor (4j-2)^2-(2+4j)^2 ?

The solution to factor (4j-2)^2-(2+4j)^2 is -32j

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factor (4j-2)^2-(2+4j)^2

factor

(4 j - 2)^{2} - (2 + 4 j)^{2}

- 32 j

Solution steps

(4 j - 2)^{2} - (2 + 4 j)^{2}

Apply Difference of Two Squares Formula:

x^{2} - y^{2} = (x + y) (x - y)

(4 j - 2)^{2} - (2 + 4 j)^{2} = ((4 j - 2) + (2 + 4 j)) ((4 j - 2) - (2 + 4 j))

= ((4 j - 2) + (2 + 4 j)) ((4 j - 2) - (2 + 4 j))

Factor

(4 j - 2) + (2 + 4 j) : 8 j

Factor

(4 j - 2) - (2 + 4 j) : - 4

= 8 j (- 4)

Multiply the numbers:

8 (- 4) = - 32

= - 32 j

60 a + 64 \geq 80 a - 9260 a + 64 \geq 80 a - 92

k^{2} + k - 2

3^{2} \cdot 3^{4}

6^{2}

What is factor (4j-2)^2-(2+4j)^2 ?
The solution to factor (4j-2)^2-(2+4j)^2 is -32j