What are the solutions to the equation 2x^2-11x+5=0 ?

The solutions to the equation 2x^2-11x+5=0 are x=5,x= 1/2

Find the zeros of 2x^2-11x+5=0

The zeros of 2x^2-11x+5=0 are x=5,x= 1/2

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2 x^{2} - 11 x + 5 = 0

x = 5, x = \frac{1}{2}

Decimal Notation

x = 5, x = 0.5

Solution steps

2 x^{2} - 11 x + 5 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 11 ) \pm ( - 11 ) ^{2} - 4 \cdot 2 \cdot 5}{2 \cdot 2}

(- 11)^{2} - 4 \cdot 2 \cdot 5 = 9

x_{1, 2} = \frac{- ( - 11 ) \pm 9}{2 \cdot 2}

Separate the solutions

x_{1} = \frac{- ( - 11 ) + 9}{2 \cdot 2}, x_{2} = \frac{- ( - 11 ) - 9}{2 \cdot 2}

x = \frac{- ( - 11 ) + 9}{2 \cdot 2} : 5

x = \frac{- ( - 11 ) - 9}{2 \cdot 2} : \frac{1}{2}

The solutions to the quadratic equation are:

x = 5, x = \frac{1}{2}

6 (4 c + 2) - 6 (2 c - 2)

x^{2} + 6 x = 12

\frac{5}{3 - 2 i}

3 x^{2} + 4 x

What are the solutions to the equation 2x^2-11x+5=0 ?
The solutions to the equation 2x^2-11x+5=0 are x=5,x= 1/2
Find the zeros of 2x^2-11x+5=0
The zeros of 2x^2-11x+5=0 are x=5,x= 1/2