What is (x^2-1)/(x^2-4x-5) ?

The solution to (x^2-1)/(x^2-4x-5) is (x-1)/(x-5)

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simplify (x^2-1)/(x^2-4x-5)

simplify

\frac{x ^{2} - 1}{x ^{2} - 4 x - 5}

\frac{x - 1}{x - 5}

Solution steps

\frac{x ^{2} - 1}{x ^{2} - 4 x - 5}

Factor

x^{2} - 1 : (x + 1) (x - 1)

= \frac{( x + 1 ) ( x - 1 )}{x ^{2} - 4 x - 5}

Factor

x^{2} - 4 x - 5 : (x + 1) (x - 5)

= \frac{( x + 1 ) ( x - 1 )}{( x + 1 ) ( x - 5 )}

Cancel the common factor:

x + 1

= \frac{x - 1}{x - 5}

\frac{9}{2} - 9

400 0^{2}

\frac{1}{2} \times \frac{1}{6}

- 2 (3 x + 1) (x + 2) (x - 3)

1.44