What is expand (2x+5)(4x-3)(5x-4) ?

The solution to expand (2x+5)(4x-3)(5x-4) is 40x^3+38x^2-131x+60

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expand (2x+5)(4x-3)(5x-4)

expand

(2 x + 5) (4 x - 3) (5 x - 4)

40 x^{3} + 38 x^{2} - 131 x + 60

Solution steps

(2 x + 5) (4 x - 3) (5 x - 4)

Expand

(2 x + 5) (4 x - 3) (5 x - 4) : (8 x^{2} + 14 x - 15) (5 x - 4)

= (8 x^{2} + 14 x - 15) (5 x - 4)

Distribute parentheses

= 8 x^{2} \cdot 5 x + 8 x^{2} (- 4) + 14 x \cdot 5 x + 14 x (- 4) - 15 \cdot 5 x - 15 (- 4)

Simplify

8 x^{2} \cdot 5 x + 8 x^{2} (- 4) + 14 x \cdot 5 x + 14 x (- 4) - 15 \cdot 5 x - 15 (- 4) : 40 x^{3} + 38 x^{2} - 131 x + 60

= 40 x^{3} + 38 x^{2} - 131 x + 60

\frac{5 x ^{7} y ^{5}}{10 x y ^{3}}

19 \times 6

15 x^{2} + 16 x - 15

x^{4} + 2 x^{3} - 9 x^{2} - 2 x + 8

x^{3} - 6 x^{2} + 61 x - 106

What is expand (2x+5)(4x-3)(5x-4) ?
The solution to expand (2x+5)(4x-3)(5x-4) is 40x^3+38x^2-131x+60