What are the solutions to the equation x^2+12x-7=0 ?

The solutions to the equation x^2+12x-7=0 are x=-6+sqrt(43),x=-6-sqrt(43)

Find the zeros of x^2+12x-7=0

The zeros of x^2+12x-7=0 are x=-6+sqrt(43),x=-6-sqrt(43)

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x^{2} + 12 x - 7 = 0

x = - 6 + 43, x = - 6 - 43

Decimal Notation

x = 0.55743 \dots, x = - 12.55743 \dots

Solution steps

x^{2} + 12 x - 7 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 12 \pm 1 2 ^{2} - 4 \cdot 1 \cdot ( - 7 )}{2 \cdot 1}

1 2^{2} - 4 \cdot 1 \cdot (- 7) = 243

x_{1, 2} = \frac{- 12 \pm 2 43}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 12 + 2 43}{2 \cdot 1}, x_{2} = \frac{- 12 - 2 43}{2 \cdot 1}

x = \frac{- 12 + 2 43}{2 \cdot 1} : - 6 + 43

x = \frac{- 12 - 2 43}{2 \cdot 1} : - 6 - 43

The solutions to the quadratic equation are:

x = - 6 + 43, x = - 6 - 43

n^{2} - 2 n - 15

6 x^{3} y + 48 y^{4}

1 + 14 - (14 - 1)

x^{2} + 18 x + 81 = 25

\frac{7}{100} x^{2} - \frac{y}{121}

What are the solutions to the equation x^2+12x-7=0 ?
The solutions to the equation x^2+12x-7=0 are x=-6+sqrt(43),x=-6-sqrt(43)
Find the zeros of x^2+12x-7=0
The zeros of x^2+12x-7=0 are x=-6+sqrt(43),x=-6-sqrt(43)