What are the solutions to the equation 5y^2=-20y ?

The solutions to the equation 5y^2=-20y are y=0,y=-4

Find the zeros of 5y^2=-20y

The zeros of 5y^2=-20y are y=0,y=-4

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5 y^{2} = - 20 y

y = 0, y = - 4

Solution steps

5 y^{2} = - 20 y

Move

20 y

to the left side

5 y^{2} + 20 y = 0

Factor

5 y^{2} + 20 y : 5 y (y + 4)

5 y (y + 4) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

y = 0 or y + 4 = 0

Solve

y + 4 = 0 : y = - 4

The solutions to the quadratic equation are:

y = 0, y = - 4

7 (a - 10) = 13 - 2 (2 a + 3)

\frac{z}{6} = 8

\frac{7 x ^{- 1} y ^{3}}{x ^{2} y ^{- 2}} \cdot \frac{( 3 x y ^{2} ) ^{- 1}}{x y}

2 x + 5 = 0

5 y^{2} + 10 y = 0

What are the solutions to the equation 5y^2=-20y ?
The solutions to the equation 5y^2=-20y are y=0,y=-4
Find the zeros of 5y^2=-20y
The zeros of 5y^2=-20y are y=0,y=-4