What is (7x^{-1}y^3)/(x^2y^{-2)}*((3xy^2)^{-1})/(xy) ?

The solution to (7x^{-1}y^3)/(x^2y^{-2)}*((3xy^2)^{-1})/(xy) is (7y^2)/(3x^5)

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simplify (7x^{-1}y^3)/(x^2y^{-2)}*((3xy^2)^{-1})/(xy)

simplify

\frac{7 x ^{- 1} y ^{3}}{x ^{2} y ^{- 2}} \cdot \frac{( 3 x y ^{2} ) ^{- 1}}{x y}

\frac{7 y ^{2}}{3 x ^{5}}

Solution steps

\frac{7 x ^{- 1} y ^{3}}{x ^{2} y ^{- 2}} \cdot \frac{( 3 x y ^{2} ) ^{- 1}}{x y}

Cancel

\frac{7 x ^{- 1} y ^{3}}{x ^{2} y ^{- 2}} : \frac{7 y ^{5}}{x ^{3}}

= \frac{7 y ^{5}}{x ^{3}} \cdot \frac{( 3 x y ^{2} ) ^{- 1}}{x y}

Simplify

\frac{( 3 x y ^{2} ) ^{- 1}}{x y} : \frac{1}{3 x y ^{2} x y}

= \frac{7 y ^{5}}{x ^{3}} \cdot \frac{1}{3 x y ^{2} x y}

Apply the fraction rule:

\frac{a}{b} \cdot \frac{c}{d} = \frac{a \cdot c}{b \cdot d}

= \frac{7 y ^{5} \cdot 1}{x ^{3} \cdot 3 x y ^{2} x y}

Multiply the numbers:

7 \cdot 1 = 7

= \frac{7 y ^{5}}{x ^{3} \cdot 3 x y ^{2} x y}

Simplify

\frac{y ^{5}}{y ^{2}} : y^{3}

= \frac{7 y ^{3}}{x ^{3} \cdot 3 xx y}

Simplify

\frac{y ^{3}}{y} : y^{2}

= \frac{7 y ^{2}}{x ^{3} \cdot 3 xx}

Simplify

x^{3} xx : x^{5}

= \frac{7 y ^{2}}{x ^{5} \cdot 3}

= \frac{7 y ^{2}}{3 x ^{5}}

2 x + 5 = 0

5 y^{2} + 10 y = 0

6 q^{2} = 8 q - 3

x - 12 < - 11

(2 x - 3) (x + 7) + (2 x + 3) (x - 7) = - 26

What is (7x^{-1}y^3)/(x^2y^{-2)}*((3xy^2)^{-1})/(xy) ?
The solution to (7x^{-1}y^3)/(x^2y^{-2)}*((3xy^2)^{-1})/(xy) is (7y^2)/(3x^5)