What are the solutions to the equation (2x-3)(x+7)+(2x+3)(x-7)=-26 ?

The solutions to the equation (2x-3)(x+7)+(2x+3)(x-7)=-26 are x=2,x=-2

Find the zeros of (2x-3)(x+7)+(2x+3)(x-7)=-26

The zeros of (2x-3)(x+7)+(2x+3)(x-7)=-26 are x=2,x=-2

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(2 x - 3) (x + 7) + (2 x + 3) (x - 7) = - 26

x = 2, x = - 2

Solution steps

(2 x - 3) (x + 7) + (2 x + 3) (x - 7) = - 26

Expand

(2 x - 3) (x + 7) + (2 x + 3) (x - 7) : 4 x^{2} - 42

4 x^{2} - 42 = - 26

Move

26

to the left side

4 x^{2} - 16 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 0 \pm 0 ^{2} - 4 \cdot 4 ( - 16 )}{2 \cdot 4}

0^{2} - 4 \cdot 4 (- 16) = 16

x_{1, 2} = \frac{- 0 \pm 16}{2 \cdot 4}

Separate the solutions

x_{1} = \frac{- 0 + 16}{2 \cdot 4}, x_{2} = \frac{- 0 - 16}{2 \cdot 4}

x = \frac{- 0 + 16}{2 \cdot 4} : 2

x = \frac{- 0 - 16}{2 \cdot 4} : - 2

The solutions to the quadratic equation are:

x = 2, x = - 2

4 \leq x < 10

∣ - 8 + 9 ∣

13 p^{2} - 3 = 4209

a^{2} - 8 a - 9 = 0

6 x^{2} + 24 x - 30

What are the solutions to the equation (2x-3)(x+7)+(2x+3)(x-7)=-26 ?
The solutions to the equation (2x-3)(x+7)+(2x+3)(x-7)=-26 are x=2,x=-2
Find the zeros of (2x-3)(x+7)+(2x+3)(x-7)=-26
The zeros of (2x-3)(x+7)+(2x+3)(x-7)=-26 are x=2,x=-2