What are the solutions to the equation a^2-8a-9=0 ?

The solutions to the equation a^2-8a-9=0 are a=9,a=-1

Find the zeros of a^2-8a-9=0

The zeros of a^2-8a-9=0 are a=9,a=-1

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a^{2} - 8 a - 9 = 0

a = 9, a = - 1

Solution steps

a^{2} - 8 a - 9 = 0

Solve with the quadratic formula

a_{1, 2} = \frac{- ( - 8 ) \pm ( - 8 ) ^{2} - 4 \cdot 1 \cdot ( - 9 )}{2 \cdot 1}

(- 8)^{2} - 4 \cdot 1 \cdot (- 9) = 10

a_{1, 2} = \frac{- ( - 8 ) \pm 10}{2 \cdot 1}

Separate the solutions

a_{1} = \frac{- ( - 8 ) + 10}{2 \cdot 1}, a_{2} = \frac{- ( - 8 ) - 10}{2 \cdot 1}

a = \frac{- ( - 8 ) + 10}{2 \cdot 1} : 9

a = \frac{- ( - 8 ) - 10}{2 \cdot 1} : - 1

The solutions to the quadratic equation are:

a = 9, a = - 1

6 x^{2} + 24 x - 30

8 x + 64

9 x^{2} - 2 x

\frac{2}{5} v + 13 < 17

x^{2} + (- \frac{1}{5})^{2} = 1

What are the solutions to the equation a^2-8a-9=0 ?
The solutions to the equation a^2-8a-9=0 are a=9,a=-1
Find the zeros of a^2-8a-9=0
The zeros of a^2-8a-9=0 are a=9,a=-1