What are the solutions to the equation x^2+(-1/5)^2=1 ?

The solutions to the equation x^2+(-1/5)^2=1 are x=(2sqrt(6))/5 ,x=-(2sqrt(6))/5

Find the zeros of x^2+(-1/5)^2=1

The zeros of x^2+(-1/5)^2=1 are x=(2sqrt(6))/5 ,x=-(2sqrt(6))/5

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x^{2} + (- \frac{1}{5})^{2} = 1

x = \frac{2 6}{5}, x = - \frac{2 6}{5}

Decimal Notation

x = 0.97979 \dots, x = - 0.97979 \dots

Solution steps

x^{2} + (- \frac{1}{5})^{2} = 1

Expand

x^{2} + (- \frac{1}{5})^{2} : x^{2} + \frac{1}{25}

x^{2} + \frac{1}{25} = 1

Move

\frac{1}{25}

to the right side

x^{2} = 1 - \frac{1}{25}

Simplify

1 - \frac{1}{25} : \frac{24}{25}

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

x = \frac{24}{25}, x = - \frac{24}{25}

\frac{24}{25} = \frac{2 6}{5}

- \frac{24}{25} = - \frac{2 6}{5}

x = \frac{2 6}{5}, x = - \frac{2 6}{5}

\frac{2}{\frac{1}{9}}

- 16 < 6 k + 2 < 0

\frac{4 x y + 4 x z}{8 x z + 8 x ^{2}}

5 w^{2} - 20 = 0

9 = \frac{h}{9}

What are the solutions to the equation x^2+(-1/5)^2=1 ?
The solutions to the equation x^2+(-1/5)^2=1 are x=(2sqrt(6))/5 ,x=-(2sqrt(6))/5
Find the zeros of x^2+(-1/5)^2=1
The zeros of x^2+(-1/5)^2=1 are x=(2sqrt(6))/5 ,x=-(2sqrt(6))/5