What are the solutions to the equation (x)(x-2)=360 ?

The solutions to the equation (x)(x-2)=360 are x=20,x=-18

Find the zeros of (x)(x-2)=360

The zeros of (x)(x-2)=360 are x=20,x=-18

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(x) (x - 2) = 360

x = 20, x = - 18

Solution steps

(x) (x - 2) = 360

Expand

(x) (x - 2) : x^{2} - 2 x

x^{2} - 2 x = 360

Move

360

to the left side

x^{2} - 2 x - 360 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 2 ) \pm ( - 2 ) ^{2} - 4 \cdot 1 \cdot ( - 360 )}{2 \cdot 1}

(- 2)^{2} - 4 \cdot 1 \cdot (- 360) = 38

x_{1, 2} = \frac{- ( - 2 ) \pm 38}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 2 ) + 38}{2 \cdot 1}, x_{2} = \frac{- ( - 2 ) - 38}{2 \cdot 1}

x = \frac{- ( - 2 ) + 38}{2 \cdot 1} : 20

x = \frac{- ( - 2 ) - 38}{2 \cdot 1} : - 18

The solutions to the quadratic equation are:

x = 20, x = - 18

9175

\frac{5 - 2 i}{4 + 2 i}

\frac{( 3 y + 4 )}{5} - \frac{( y + 2 )}{2} = \frac{( 4 y - 1 )}{10}

5^{\frac{1}{2}} \cdot 4 5^{\frac{1}{2}}

x^{4} - x^{3} - x + 1

What are the solutions to the equation (x)(x-2)=360 ?
The solutions to the equation (x)(x-2)=360 are x=20,x=-18
Find the zeros of (x)(x-2)=360
The zeros of (x)(x-2)=360 are x=20,x=-18