What is the answer to ((3y+4))/5-((y+2))/2 =((4y-1))/(10) ?

The answer to ((3y+4))/5-((y+2))/2 =((4y-1))/(10) is y=-1/3

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((3y+4))/5-((y+2))/2 =((4y-1))/(10)

\frac{( 3 y + 4 )}{5} - \frac{( y + 2 )}{2} = \frac{( 4 y - 1 )}{10}

y = - \frac{1}{3}

Decimal Notation

y = - 0.33333 \dots

Solution steps

\frac{( 3 y + 4 )}{5} - \frac{( y + 2 )}{2} = \frac{( 4 y - 1 )}{10}

\frac{3 y + 4}{5} - \frac{y + 2}{2} = \frac{( 4 y - 1 )}{10}

Multiply by LCM

2 (3 y + 4) - 5 (y + 2) = 4 y - 1

Expand

2 (3 y + 4) - 5 (y + 2) : y - 2

y - 2 = 4 y - 1

Move

2

to the right side

y = 4 y + 1

Move

4 y

to the left side

- 3 y = 1

Divide both sides by

- 3

y = - \frac{1}{3}

5^{\frac{1}{2}} \cdot 4 5^{\frac{1}{2}}

x^{4} - x^{3} - x + 1

4 x^{2} - 4 x = 0

x^{2} - 2 x - 143

\frac{( 1.05 - 0.95 ) ^{2}}{12}

What is the answer to ((3y+4))/5-((y+2))/2 =((4y-1))/(10) ?
The answer to ((3y+4))/5-((y+2))/2 =((4y-1))/(10) is y=-1/3
Solve for y: ((3y+4))/5-((y+2))/2 =((4y-1))/(10)
The solution is y=-1/3