What is expand (3x+1)(x+2)(x-3) ?

The solution to expand (3x+1)(x+2)(x-3) is 3x^3-2x^2-19x-6

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expand (3x+1)(x+2)(x-3)

expand

(3 x + 1) (x + 2) (x - 3)

3 x^{3} - 2 x^{2} - 19 x - 6

Solution steps

(3 x + 1) (x + 2) (x - 3)

Expand

(3 x + 1) (x + 2) (x - 3) : (3 x^{2} + 7 x + 2) (x - 3)

= (3 x^{2} + 7 x + 2) (x - 3)

Distribute parentheses

= 3 x^{2} x + 3 x^{2} (- 3) + 7 xx + 7 x (- 3) + 2 x + 2 (- 3)

Simplify

3 x^{2} x + 3 x^{2} (- 3) + 7 xx + 7 x (- 3) + 2 x + 2 (- 3) : 3 x^{3} - 2 x^{2} - 19 x - 6

= 3 x^{3} - 2 x^{2} - 19 x - 6

- 9 \times 7

(a - 3)^{5}

(- 1 - i)^{16}

(- 3 x + 5) (x^{2} + 7 x + 5)

14 + 83

What is expand (3x+1)(x+2)(x-3) ?
The solution to expand (3x+1)(x+2)(x-3) is 3x^3-2x^2-19x-6