What are the solutions to the equation 4x^2-4x=0 ?

The solutions to the equation 4x^2-4x=0 are x=1,x=0

Find the zeros of 4x^2-4x=0

The zeros of 4x^2-4x=0 are x=1,x=0

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4 x^{2} - 4 x = 0

x = 1, x = 0

Solution steps

4 x^{2} - 4 x = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 4 ) \pm ( - 4 ) ^{2} - 4 \cdot 4 \cdot 0}{2 \cdot 4}

(- 4)^{2} - 4 \cdot 4 \cdot 0 = 4

x_{1, 2} = \frac{- ( - 4 ) \pm 4}{2 \cdot 4}

Separate the solutions

x_{1} = \frac{- ( - 4 ) + 4}{2 \cdot 4}, x_{2} = \frac{- ( - 4 ) - 4}{2 \cdot 4}

x = \frac{- ( - 4 ) + 4}{2 \cdot 4} : 1

x = \frac{- ( - 4 ) - 4}{2 \cdot 4} : 0

The solutions to the quadratic equation are:

x = 1, x = 0

x^{2} - 2 x - 143

\frac{( 1.05 - 0.95 ) ^{2}}{12}

3 x - 4 \leq 8

\frac{3}{4} (- 6)

x^{2} + 2 x + 4 < 0

What are the solutions to the equation 4x^2-4x=0 ?
The solutions to the equation 4x^2-4x=0 are x=1,x=0
Find the zeros of 4x^2-4x=0
The zeros of 4x^2-4x=0 are x=1,x=0