What is (2^{n+1}-2^{n+2})/(2^{n-1)-2^{n-2}} ?

The solution to (2^{n+1}-2^{n+2})/(2^{n-1)-2^{n-2}} is -8

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simplify (2^{n+1}-2^{n+2})/(2^{n-1)-2^{n-2}}

simplify

\frac{2 ^{n + 1} - 2 ^{n + 2}}{2 ^{n - 1} - 2 ^{n - 2}}

- 8

Solution steps

\frac{2 ^{n + 1} - 2 ^{n + 2}}{2 ^{n - 1} - 2 ^{n - 2}}

Factor

2^{n + 1} - 2^{n + 2} : - 2^{1 + n}

= - \frac{2 ^{1 + n}}{2 ^{n - 1} - 2 ^{n - 2}}

Factor

2^{n - 1} - 2^{n - 2} : 2^{- 2 + n}

= - \frac{2 ^{1 + n}}{2 ^{- 2 + n}}

Cancel

- \frac{2 ^{1 + n}}{2 ^{- 2 + n}} : - 2^{3}

= - 2^{3}

2^{3} = 8

= - 8

2 - 192

+ 4 z^{2} - 20 z + 25

1000 e^{0.05 \cdot 7}

\frac{5 x ^{7} y ^{7}}{25 x ^{7} y ^{2}}

- 2 x \times (- 2) x

What is (2^{n+1}-2^{n+2})/(2^{n-1)-2^{n-2}} ?
The solution to (2^{n+1}-2^{n+2})/(2^{n-1)-2^{n-2}} is -8