What is the answer to 4(2-(3(z+1)-2(z+1)))=-2z ?

The answer to 4(2-(3(z+1)-2(z+1)))=-2z is z=2

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4(2-(3(z+1)-2(z+1)))=-2z

4 (2 - (3 (z + 1) - 2 (z + 1))) = - 2 z

z = 2

Solution steps

4 (2 - (3 (z + 1) - 2 (z + 1))) = - 2 z

Expand

4 (2 - (3 (z + 1) - 2 (z + 1))) : - 4 z + 4

- 4 z + 4 = - 2 z

Move

4

to the right side

- 4 z = - 2 z - 4

Move

2 z

to the left side

- 2 z = - 4

Divide both sides by

- 2

z = 2

x^{2} + 6 x = 16

- (\frac{1}{3})^{1}

(x - 4)^{2} = x (x - 9) + 40

z^{4} - 16

What is the answer to 4(2-(3(z+1)-2(z+1)))=-2z ?
The answer to 4(2-(3(z+1)-2(z+1)))=-2z is z=2
Solve for z: 4(2-(3(z+1)-2(z+1)))=-2z
The solution is z=2