What are the solutions to the equation -16t^2+70t-45=0 ?

The solutions to the equation -16t^2+70t-45=0 are t=(35-sqrt(505))/(16),t=(35+sqrt(505))/(16)

Find the zeros of -16t^2+70t-45=0

The zeros of -16t^2+70t-45=0 are t=(35-sqrt(505))/(16),t=(35+sqrt(505))/(16)

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- 16 t^{2} + 70 t - 45 = 0

t = \frac{35 - 505}{16}, t = \frac{35 + 505}{16}

Decimal Notation

t = 0.78298 \dots, t = 3.59201 \dots

Solution steps

- 16 t^{2} + 70 t - 45 = 0

Solve with the quadratic formula

t_{1, 2} = \frac{- 70 \pm 7 0 ^{2} - 4 ( - 16 ) ( - 45 )}{2 ( - 16 )}

7 0^{2} - 4 (- 16) (- 45) = 2505

t_{1, 2} = \frac{- 70 \pm 2 505}{2 ( - 16 )}

Separate the solutions

t_{1} = \frac{- 70 + 2 505}{2 ( - 16 )}, t_{2} = \frac{- 70 - 2 505}{2 ( - 16 )}

t = \frac{- 70 + 2 505}{2 ( - 16 )} : \frac{35 - 505}{16}

t = \frac{- 70 - 2 505}{2 ( - 16 )} : \frac{35 + 505}{16}

The solutions to the quadratic equation are:

t = \frac{35 - 505}{16}, t = \frac{35 + 505}{16}

4^{2} + 7^{2} = c^{2}

44 x^{2} z^{5} + 11 x^{3} y^{3} z^{2}

- 18 - 6 x = 6 (1 + 3 x)

\frac{1}{2 a} - \frac{2}{3 b} + 14 + \frac{1}{7 a}

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What are the solutions to the equation -16t^2+70t-45=0 ?
The solutions to the equation -16t^2+70t-45=0 are t=(35-sqrt(505))/(16),t=(35+sqrt(505))/(16)
Find the zeros of -16t^2+70t-45=0
The zeros of -16t^2+70t-45=0 are t=(35-sqrt(505))/(16),t=(35+sqrt(505))/(16)